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Question Number 31822 by Tinkutara last updated on 15/Mar/18

	Answered by rahul 19 last updated on 15/Mar/18

	$10.368 s e c (l o o s e) .$ $t h e f o r m u l a i s Δ T = \frac{1}{2} α (Δ θ) T$ $h e r e γ = 36 \times 10^{- 6} a n d$ $w e k n o w 3 α = γ$ $\Rightarrow α = 12 \times 10^{- 6} .$ $p l u g g i n g t h e v a l u e s i n f o r m u l a w e g e t,$ $\Rightarrow \frac{1}{2} . 12 \times 10^{- 6} . (40 - 20) . 24.60.60$ $\Rightarrow 10.368 s e c .$
	Commented by Tinkutara last updated on 15/Mar/18
	Correct, can you please explain? Actually I know the method but initial time period should be taken 1s or 2s?
	Commented by rahul 19 last updated on 15/Mar/18

	$i a m n o t a b l e t o u n d e r s t a n d, w h a t$ $a r e u t r y i n g t o s a y ?$
	Commented by Tinkutara last updated on 15/Mar/18

	$\frac{T^{'}}{T} = \sqrt{\frac{l^{'}}{l}} = \sqrt{1 + α Δ θ} = 1 + \frac{1}{2} α Δ θ$ $\frac{Δ T}{T} = \frac{α Δ θ}{2}$ $Δ T = \frac{T α Δ θ}{2}$ $S o w h a t t o t a k e i n i t i a l T ?$ $A n d t h e n w h y m u l t i p l y b y 24 \times 60 \times 60 ?$
	Commented by rahul 19 last updated on 15/Mar/18

	$1 d a y = 24 \times 60 \times 60 s e c .$
	Commented by Tinkutara last updated on 15/Mar/18
	Did you take here T=1s?
	Commented by rahul 19 last updated on 15/Mar/18

	$n o i h a v e t a k e n 1 d a y a s m e n t i o n e d$ $i n q . (l o o s e / g a i n p e r d a y) .$
	Commented by Tinkutara last updated on 15/Mar/18
	Thank you very much Sir! I got the answer. ��
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