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Question Number 33430 by rahul 19 last updated on 16/Apr/18

Commented by rahul 19 last updated on 16/Apr/18

$$Here\mathit{E}=electricfield.$$$$\mathit{V}=Electrostaticpotential.$$

Commented by ajfour last updated on 16/Apr/18

$$E_x=-\frac{\partial V}{\partial x}$$$$hence\left(B\right).$$

Commented by rahul 19 last updated on 16/Apr/18

$$ohh,yes!$$$$thankusir.$$

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