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Question Number 37906 by mondodotto@gmail.com last updated on 19/Jun/18

Answered by tanmay.chaudhury50@gmail.com last updated on 19/Jun/18

$$joinoBso<OBC={90}^o$$$$<BEO=<OBE=x\{sinceOB=OE=radius\}$$$$x+{18}^o+{90}^o+x={180}^o$$$$2x={72}^{o}x={36}^o$$$$<CEB={36}^o<EBC={90}^o+{36}^o={126}^o$$

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