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Question Number 38291 by Tinkutara last updated on 23/Jun/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18

	$E = \frac{1}{4 Π ϵ_{0}} \times \frac{e}{d^{2}} e = c h a r g e o f e l e c t r o n$ $= 9 \times 10^{9} \times \frac{1 \times 1.6 \times 10^{- 19}}{{(10^{- 10})}^{2}} = 14.4 \times 10^{9 - 19 + 20}$ $= 1.44 \times 10^{11} f o r e l e c t r o n$ $s a m e v a l u e f o r p r o t o n B u t o p p o s i t e d i r e c t i o n$ $s o n e t e l e c t r i c f i e l d i s z e r o$
	Commented by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18

	Commented by Tinkutara last updated on 24/Jun/18
	Answer is wrong, Sir.
	Commented by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18

	$p l s c h e c k n o w i f o r g o t t o v e c t o r a d d i t i o n$ $o f p r o t o n a n d e l e c t r o n . . .$
	Commented by Tinkutara last updated on 24/Jun/18
	Answer given is b.
	Commented by tanmay.chaudhury50@gmail.com last updated on 24/Jun/18

	$i n s u b a t o m i c c a s e p r o t o n a l s o c o m e s t o p l a y . .$ $b e c a u s e s e p a r a t i o n i n A^{0} . . . p l s s e a r c h i n$ $w i k i p e d i a o r p o s t t h e s a m e q u e s t i o n i n Q U O R A$
	Commented by prakash jain last updated on 24/Jun/18
	distance between alpha particle in electron is 1 A then what is the distance between alpha particle and proton? I think proton will give negilgible field.
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