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Question Number 38419 by Rio Mike last updated on 25/Jun/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 25/Jun/18

	$m_{B} g - T - f r i c t i o n = m_{B} a$ $T - μ m_{A} g = m_{A} a$ $a s p e r q u e s t i o n b l o c k B h a n g s f r e e l y s o$ $f r i c t i o n b e t w e e n w o o d e n b i g b l o c k a n d m a s s$ $m_{B} i s c o n s i d e r e d z e r o$ $m_{B} g - T = m_{B} a$ $T - μ m_{A} g = m_{A} a$ $a d d i n g$ $m_{B} g - μ m_{A} g = a (m_{A} + m_{B})$ $3 \times 10 - μ \times 2 \times 10 = 4 (3 + 2)$ $30 - 20 = 20 μ$ $μ = \frac{10}{20} = 0.5$ $T = m_{B} g - m_{B} a = 3 (10 - 4) = 18 N$
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