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Question Number 40591 by mondodotto@gmail.com last updated on 24/Jul/18

Commented by mondodotto@gmail.com last updated on 24/Jul/18

$$\mathbf{roman}\left(\mathbf{i}\right)\mathbf{please}$$

Answered by MJS last updated on 24/Jul/18

$$1-3-11-21-43-32-9$$$$\mathrm{sum}=120$$$$120:4=30\mathrm{persons}\mathrm{in}\mathrm{each}\mathrm{quartile}$$$$1+3+11+15\mathrm{of}21\Rightarrow \mathrm{q}1\in [60-69]$$$$6\mathrm{of}21+24\mathrm{of}43\Rightarrow \mathrm{median}\in [70-79]$$$$19\mathrm{of}43+11\mathrm{of}32\Rightarrow \mathrm{q}3\in [80-89]$$$$21\mathrm{of}32+9$$

Commented by mondodotto@gmail.com last updated on 25/Jul/18

$$\mathbf{sir}\mathbf{i}\mathbf{stil}\mathbf{dont}\mathbf{undstnd}\mathbf{this}\mathbf{way}$$

Commented by MJS last updated on 25/Jul/18

$$\mathrm{to}\mathrm{find}\mathrm{the}\mathrm{borders}\mathrm{of}\mathrm{the}\mathrm{quartiles}\mathrm{you}\mathrm{have}$$$$\mathrm{to}\mathrm{make}\mathrm{a}\mathrm{sorted}\mathrm{set}\mathrm{of}\mathrm{all}\mathrm{the}\mathrm{items}\mathrm{and}\mathrm{cut}$$$$\mathrm{this}\mathrm{set}\mathrm{in}4\mathrm{parts}\mathrm{of}\mathrm{equal}\mathrm{lenght}.{\mathrm{there}}^{\prime }\mathrm{s}\mathrm{no}$$$$\mathrm{other}\mathrm{way}.$$$$\mathrm{example}:$$$$\mathrm{the}\mathrm{ages}\mathrm{of}18\mathrm{family}\mathrm{members}$$$$\{6,9,10,22,24,25,28,38,41,45,46,48,49,67,69,74,75,86\}$$$$1^{\mathrm{st}}\mathrm{half}$$$$\{6,9,10,22,24,25,28,38,41\}$$$$2^{\mathrm{nd}}\mathrm{half}$$$$\{45,46,48,49,67,69,74,75,86\}$$$$median=\frac{41+45}{2}=43$$$$1^{\mathrm{st}}\mathrm{quarter}$$$$\{6,9,10,22,24\}$$$$2^{\mathrm{nd}}\mathrm{quarter}$$$$\{24,25,28,38,41\}$$$$q1=24$$$$3^{\mathrm{rd}}\mathrm{quarter}$$$$\{45,46,48,49,67\}$$$$4^{\mathrm{th}}\mathrm{quarter}$$$$\{67,69,74,75,86\}$$$$q3=67$$$$\{min,q1,med,q3,max\}=\{6,24,43,67,86\}$$

Commented by mondodotto@gmail.com last updated on 25/Jul/18

$$\mathrm{thank}\mathrm{you}\mathrm{sir}$$$$$$

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