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Question Number 43571 by rahul 19 last updated on 12/Sep/18

Answered by ajfour last updated on 21/Sep/18

$${\overline{v}}_I=({\overline{v}}_O-{\overline{v}}_M)-2{({\overline{v}}_O-{\overline{v}}_M)}_{\mathit{z}}+{\overline{v}}_M$$$${\overline{v}}_I={\overline{v}}_O-2{({\overline{v}}_O-{\overline{v}}_M)}_{\mathit{z}}$$$$=5\hat{i}-3\hat{j}-11\hat{k}-2(-11\hat{k}+3\hat{k})$$$$=(5\hat{i}-3\hat{j}+5\hat{k})m/s.$$$$$$

Commented by rahul 19 last updated on 15/Sep/18

$$\mathrm{why}\mathrm{velocity}\mathrm{of}\mathrm{image}\mathrm{in}x\mathrm{\&}\mathrm{y}$$$$\mathrm{plane}\mathrm{remained}\mathrm{same}\mathrm{as}\mathrm{that}\mathrm{of}\mathrm{object}??$$

Commented by ajfour last updated on 21/Sep/18

$$fromamirrorparalleltox-y$$$$planeonlythe{v}_{z}of$$$$imagecanundergoachange,$$$$(thinkyourself,obviousbut$$$$difficultformetoexplain,i$$$${haven}^{\prime }tevenusedthisfact).$$

Commented by rahul 19 last updated on 21/Sep/18

$$I\mathrm{want}\mathrm{to}\mathrm{know}\mathrm{how}\mathrm{mirror}\mathrm{is}\mathrm{parallel}$$$$\mathrm{to}x-y\mathrm{plane}?\mathrm{I}n\mathrm{the}\mathrm{ques}.\mathrm{it}\mathrm{has}$$$$\mathrm{velocity}\mathrm{in}\mathrm{all}3\mathrm{perpendicular}\mathrm{a}x\mathrm{es}!$$

Commented by ajfour last updated on 21/Sep/18

$$linearvelocityhasnothingtodo$$$$withorientation\left(here\right).$$

Commented by rahul 19 last updated on 21/Sep/18

$$oksir,thanks!$$

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