Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 48874 by behi83417@gmail.com last updated on 29/Nov/18

Commented by behi83417@gmail.com last updated on 29/Nov/18

ABC,equilateral. CD=CE=8,AD=EB=4,DE=3 ⇒ AB=?

ABC,equilateral.CD=CE=8,AD=EB=4,DE=3⇒AB=?

Answered by mr W last updated on 29/Nov/18

AB=a ((a/2)−(3/2))^2 +((((√3)a)/2)−(√(8^2 −((3/2))^2 )))^2 =4^2 (a−3)^2 +((√3)a−(√(247)))^2 =64 a^2 −6a+9+3a^2 −2(√(741))a+247=64 4a^2 −2(3+(√(741)))a+191=0 a=((3+(√(741))+(√((3+(√(741)))^2 −4×191)))/4) ⇒a=((3+(√(741))+(√(6(√(741))−14)))/4)≈10.61

AB=a(a2−32)2+(3a2−82−(32)2)2=42(a−3)2+(3a−247)2=64a2−6a+9+3a2−2741a+247=644a2−2(3+741)a+191=0a=3+741+(3+741)2−4×1914⇒a=3+741+6741−144≈10.61

Commented by behi83417@gmail.com last updated on 29/Nov/18

right answer dear mr w.thanks.

rightanswerdearmrw.thanks.

Answered by behi83417@gmail.com last updated on 29/Nov/18

Terms of Service

Privacy Policy

Contact: info@tinkutara.com