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Question Number 49252 by cesar.marval.larez@gmail.com last updated on 04/Dec/18

Answered by kaivan.ahmadi last updated on 05/Dec/18

$$★\mathrm{b}$$$${\mathrm{f}}^{\prime }\left(\mathrm{x}\right)=2\mathrm{tg}\left(\sec (\cos 5\mathrm{x}-3)\right)(1+{\mathrm{tg}}^2\left(\sec \left(\cos (5\mathrm{x}-3)\right)\right)){\left(\sec \left(\cos (5\mathrm{x}-3)\right)\right)}^{{}^{\prime }}=$$$$\mathrm{on}\mathrm{the}\mathrm{other}\mathrm{hand}$$$${\left(\sec \left(\cos (5\mathrm{x}-3)\right)\right)}^{\prime }=\sec \left(\cos (5\mathrm{x}-3)\right)\mathrm{tg}\left(\cos (5\mathrm{x}-3)\right).(-5\sin (5\mathrm{x}-3))$$$$$$

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