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Question Number 49785 by ggny last updated on 10/Dec/18

Answered by afachri last updated on 10/Dec/18

$$\left(1\right)\frac{{11}^{20}.{\left(2^{-3}\right)}^6.{\left(2^6\right)}^4}{2^4.{11}^{19}}={11}^{20-19}.2^{-18+24-4}=11.2^2$$$$=44$$$$\left(2\right)\frac{5^{15}.{\left(3^4\right)}^2}{{(3.5^2)}^7}=\frac{5^{15}.3^8}{5^{14}.3^7}=5^{15-14}.3^{8-7}=5.3=15$$$$\left(3\right)\frac{{\left(2^4\right)}^4.5^8.{\left(2^{-1}\right)}^7}{{(2.5)}^7}=\frac{2^{16}.5^8.2^{-7}}{2^7.5^7}=2^{16-7-7}.5^{8-7}$$$$=2^2.5=20$$

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