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Question Number 51884 by ajfour last updated on 31/Dec/18

Commented by ajfour last updated on 31/Dec/18

Relate radius r of the two circles  (the same) with side length a of  the equilateral triangle.

Relateradiusrofthetwocircles(thesame)withsidelengthaoftheequilateraltriangle.

Commented by mr W last updated on 01/Jan/19

(r/a)=(((√3)−(√2))/2)

ra=322

Commented by ajfour last updated on 01/Jan/19

AD = ((a(√3))/2) = AS+SM+MQ+QD  ((a(√3))/2) = 2r+(r/(cos 2θ))+(r/(cos 2θ))+r    tan θ = ((2r)/a) = t  ((a(√3))/2) = 3r+((2r[1+(((2r)/a))^2 ])/([1−(((2r)/a))^2 ]))  let    (√3) = 3t+((2t(1+t^2 ))/(1−t^2 ))  (√3)−(√3)t^2 = 3t−3t^3 +2t+2t^3   t^3 −(√3)t^2 −5t+(√3) = 0

AD=a32=AS+SM+MQ+QDa32=2r+rcos2θ+rcos2θ+rtanθ=2ra=ta32=3r+2r[1+(2ra)2][1(2ra)2]let3=3t+2t(1+t2)1t233t2=3t3t3+2t+2t3t33t25t+3=0

Commented by ajfour last updated on 01/Jan/19

Answered by mr W last updated on 01/Jan/19

let α=∠PBC  BO=CO=(a/(2 cos α))  DO=((a tan α)/2)  Δ_(BOC) =(a/2)×((a tan α)/2)=(r/2)(a+2×(a/(2 cos α)))  ((a tan α)/2)=r(1+(1/(cos α)))  ⇒r=((a sin α)/(2(1+cos α)))=(a/2) tan (α/2) ...(i)  BR=((a sin α)/(sin ((π/3)+α)))  AR=a−((a sin α)/(sin ((π/3)+α)))=((sin ((π/3)+α)−sin α)/(sin ((π/3)+α)))×a  =(((√3) cos α−sin α)/((√3) cos α+sin α))×a  CR=((a sin (π/3))/(sin ((π/3)+α)))=(((√3) a)/((√3) cos α+sin α))  Δ_(ARC) =((a sin (π/3))/2)×(((√3) cos α−sin α)/((√3) cos α+sin α))×a=(r/2)(a+(((√3) cos α−sin α)/((√3) cos α+sin α))×a+(((√3) a)/((√3) cos α+sin α)))  ⇒r=(((√3) cos α−sin α)/(2(1+2 cos α)))×a   ...(ii)  ⇒((sin α)/(1+cos α))=(((√3) cos α−sin α)/(1+2 cos α))  ⇒2 tan α+3 sin α=(√3)(1+cos α)  with t=tan (α/2)  ⇒t^3 −(√3)t^2 −5t+(√3)=0  ⇒t=(√3)−(√2)  ⇒(r/a)=(t/2)=(((√3)−(√2))/2) ≈0.1589

letα=PBCBO=CO=a2cosαDO=atanα2ΔBOC=a2×atanα2=r2(a+2×a2cosα)atanα2=r(1+1cosα)r=asinα2(1+cosα)=a2tanα2...(i)BR=asinαsin(π3+α)AR=aasinαsin(π3+α)=sin(π3+α)sinαsin(π3+α)×a=3cosαsinα3cosα+sinα×aCR=asinπ3sin(π3+α)=3a3cosα+sinαΔARC=asinπ32×3cosαsinα3cosα+sinα×a=r2(a+3cosαsinα3cosα+sinα×a+3a3cosα+sinα)r=3cosαsinα2(1+2cosα)×a...(ii)sinα1+cosα=3cosαsinα1+2cosα2tanα+3sinα=3(1+cosα)witht=tanα2t33t25t+3=0t=32ra=t2=3220.1589

Commented by ajfour last updated on 01/Jan/19

Thank you Sir.

ThankyouSir.

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