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Question Number 5275 by sanusihammed last updated on 03/May/16

Answered by Rasheed Soomro last updated on 04/May/16

$$\mathrm{Three}\mathrm{members}\mathrm{of}\mathrm{the}\mathrm{commetee}\mathrm{of}\mathrm{six}$$$$\mathrm{are}\mathrm{chairman},\mathrm{secratery}\mathrm{and}\mathrm{treasurer}.$$$$\mathrm{Remaining}3\mathrm{members}\mathrm{are}\mathrm{chosen}\mathrm{out}\mathrm{of}$$$$7\mathrm{members}:$$$$\left(\begin{array}{c}7\\ 3\end{array}\right)=\frac{7.6.5}{1.2.3}=35\mathrm{ways}.$$

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