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Question Number 5632 by sanusihammed last updated on 23/May/16
Answered by FilupSmith last updated on 23/May/16
Exteriorangles=360o2x+3x+x−40+x+10+x−60=3608x−90=3608x=450x=4508
Commented by sanusihammed last updated on 23/May/16
Thankssomuch
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