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Question Number 56534 by Gulay last updated on 18/Mar/19

Commented by Gulay last updated on 18/Mar/19

$$\mathrm{sir}\mathrm{could}\mathrm{you}\mathrm{help}\mathrm{me}$$

Answered by MJS last updated on 18/Mar/19

$${\log }_{b}p={\log }_{b}q\iff p=q$$$$2x-3=x+4\Rightarrow x=7$$

Commented by Gulay last updated on 18/Mar/19

$$\mathrm{thanks}\mathrm{sir}$$

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