Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 60421 by Tawa1 last updated on 20/May/19

Answered by MJS last updated on 20/May/19

$$\eta =\frac{\pi }{8}\times \frac{{pr}^4}{LQ}$$$${\eta }_{min}=\frac{\pi }{8}\times \frac{.97p\times {(.98r)}^4}{1.01L\times 1.005Q}\approx .881\frac{\pi {pr}^4}{8LQ}$$$${\eta }_{max}=\frac{\pi }{8}\times \frac{1.03p\times {(1.02r)}^4}{.99L\times .995Q}\approx 1.132\frac{\pi {pr}^4}{8LQ}$$$$\Rightarrow \max .\mathrm{\%}\mathrm{error}\mathrm{of}\eta \approx 13.2\mathrm{\%}$$

Commented by Tawa1 last updated on 20/May/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com