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Question Number 60423 by Tawa1 last updated on 20/May/19

Answered by MJS last updated on 20/May/19

$$\left(\begin{array}{c}20\\ \mathrm{\angle }30°\end{array}\right)=\left(\begin{array}{c}10\sqrt{3}\\ 10\end{array}\right)$$$$\left(\begin{array}{c}8\\ \mathrm{\angle }-50°\end{array}\right)=\left(\begin{array}{c}8\sin \frac{2\pi }{9}\\ -8\cos \frac{2\pi }{9}\end{array}\right)$$$$\left(\begin{array}{c}10\sqrt{3}\\ 10\end{array}\right)+\left(\begin{array}{c}8\sin \frac{2\pi }{9}\\ -8\cos \frac{2\pi }{9}\end{array}\right)\approx \left(\begin{array}{c}22.46\\ 3.87\end{array}\right)$$$$\mathrm{the}\mathrm{length}\mathrm{of}\mathrm{this}\mathrm{vector}\mathrm{is}22.79$$$$\mathrm{the}\mathrm{direction}\mathrm{of}\mathrm{this}\mathrm{vector}\mathrm{is}\mathrm{E}9.78°\mathrm{N}$$

Commented by Tawa1 last updated on 20/May/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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