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Question Number 61343 by bhanukumarb2@gmail.com last updated on 01/Jun/19

Answered by MJS last updated on 01/Jun/19

x=a−(1/(a−(1/(a−...))))  x=a−(1/x)  x^2 −ax+1=0  x=(a/2)±((√(a^2 −4))/2)  a=2207 ⇒ x=((2207±987(√5))/2)  (((2207±987(√5))/2))^(1/8) =(√(√(√((2207±987(√5))/2))))  step 1  (a±b(√5))^2 =((2207±987(√5))/2) ⇒ a=((47)/2), b=((21)/2)  step 2  (a±b(√5))^2 =((47±21(√5))/2) ⇒ a=(7/2), b=(3/2)  step 3  (a±b(√5))^2 =((7±3(√5))/2) ⇒ a=(3/2); b=(1/2)  result is  ((3±(√5))/2)

x=a1a1a...x=a1xx2ax+1=0x=a2±a242a=2207x=2207±987522207±987528=2207±98752step1(a±b5)2=2207±98752a=472,b=212step2(a±b5)2=47±2152a=72,b=32step3(a±b5)2=7±352a=32;b=12resultis3±52

Commented by bhanukumarb2@gmail.com last updated on 01/Jun/19

thanks sir

thankssir

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