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Question Number 61343 by bhanukumarb2@gmail.com last updated on 01/Jun/19
Answered by MJS last updated on 01/Jun/19
x=a−1a−1a−...x=a−1xx2−ax+1=0x=a2±a2−42a=2207⇒x=2207±987522207±987528=2207±98752step1(a±b5)2=2207±98752⇒a=472,b=212step2(a±b5)2=47±2152⇒a=72,b=32step3(a±b5)2=7±352⇒a=32;b=12resultis3±52
Commented by bhanukumarb2@gmail.com last updated on 01/Jun/19
thankssir
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