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Question Number 64187 by Hope last updated on 15/Jul/19

Answered by Hope last updated on 15/Jul/19

$$\frac{yz}{xyz}+\frac{4zx}{xyz}+\frac{9xy}{xyz}$$$$\frac{1^2}{x}+\frac{2^2}{y}+\frac{3^2}{z}⩾\frac{{(1+2+3)}^2}{(x+y+z)}$$$$\frac{1^2}{x}+\frac{2^2}{y}+\frac{3^2}{z}⩾\frac{36}{3}$$$$sominimumvalueis12$$

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