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Question Number 64425 by Tawa1 last updated on 17/Jul/19

Commented by Prithwish sen last updated on 17/Jul/19

$$\mathrm{Area}\mathrm{of}\mathrm{shaded}\mathrm{portion}=$$$$\mathrm{Area}\mathrm{of}\mathrm{square}-\mathrm{Area}\mathrm{of}\mathrm{quarter}\mathrm{circle}$$$$={\mathrm{a}}^2-\frac{\pi {\mathrm{a}}^2}{4}[\mathrm{if}\mathbf{a}\mathrm{be}\mathrm{the}\mathrm{side}\mathrm{of}\mathrm{the}\mathrm{square}$$$$\mathrm{then}\mathrm{it}\mathrm{is}\mathrm{also}\mathrm{the}\mathrm{radius}\mathrm{of}\mathrm{the}\mathrm{circle}\mathrm{as}\mathrm{well}]$$$$$$

Commented by Tawa1 last updated on 17/Jul/19

$$\mathrm{The}\mathrm{shape}\mathrm{is}\mathrm{a}\mathrm{square}$$

Commented by Tawa1 last updated on 17/Jul/19

$$\mathrm{Find}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{shaded}\mathrm{region}$$

Commented by Tawa1 last updated on 17/Jul/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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