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Question Number 64447 by Tawa1 last updated on 18/Jul/19

	Answered by som(math1967) last updated on 18/Jul/19

	$(4 - 3) (4 + 3) (4^{2} + 3^{2}) . . . . . (4^{32} + 3^{32}) = 4^{x} - 3^{x} ★$ $(4^{2} - 3^{2}) . . . . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $4^{64} - 3^{64} = 4^{x} - 3^{x}$ $∴ x = 64$ $★ (4 - 3) = 1$
	Commented by Tawa1 last updated on 18/Jul/19

	$God bless you sir .$
	Commented by som(math1967) last updated on 18/Jul/19

	$1 . (4 + 3) (4^{2} + 3^{2}) (4^{4} + 3^{4}) . . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $(4 - 3) (4 + 3) (4^{2} + 3^{2}) (4^{4} + 3^{4}) . . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $(4^{2} - 3^{2}) (4^{2} + 3^{2}) (4^{4} + 3^{4}) . . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $(4^{4} - 3^{4}) (4^{4} + 3^{4}) . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $(4^{8} - 3^{8}) (4^{8} + 3^{8}) . . (4^{32} + 3^{32}) = 4^{x} - 3^{x}$ $4^{64} - 3^{64} = 4^{x} - 3^{x}$
	Commented by Tawa1 last updated on 18/Jul/19

	$I appreciate your effort sir . God bless you .$
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