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Question Number 65651 by Masumsiddiqui399@gmail.com last updated on 01/Aug/19

Commented by Prithwish sen last updated on 01/Aug/19

(x−1)^2 +y^2 =0 ⇒x−1=0 and y=0  ∴x^3 +y^3 =1

(x1)2+y2=0x1=0andy=0x3+y3=1

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