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Question Number 65724 by bshahid010@gmail.com last updated on 02/Aug/19
Answered by mr W last updated on 03/Aug/19
S=sinx+cosx+1sinx+1cosx+sinxcosx+cosxsinx=sinx+cosx+sinx+cosxsinxcosx+1sinxcosx=sinx+cosx+sinx+cosx+1sinxcosxletsinx+cosx=t⇒sinxcosx=t2−12⇒S=t+2(t+1)t2−1=t+2t−1=1+(t−1)+2t−1since−2⩽t⩽2−2−1⩽t−1⩽2−1fort−1>0:S=1+(t−1)+2t−1⩾1+22=SminSminatt=2+1>2⇒impossiblefort−1<0:S=1−[(1−t)+21−t]⩽1−22=SmaxSmaxatt=1−2>−2⇒possible⇒mininmumof∣S∣is∣1−22∣=22−1≈1.828att=1−2orx=nπ−(−1)n(sin−12−22)−π4
Answered by Tanmay chaudhury last updated on 03/Aug/19
sinx+cosx=a2(12sinx+12cosx)=a2sin(π4+x)=a+1⩾sin(π4+x)⩾−1so2⩾a⩾−2tanx+cotxsin2x+cos2xcosxsinx22sinxcosx2sin2x21+sin2x−12(sinx+cosx)2−12a2−1secx+cosecx=sinx+cosxsinxcosx=(sinx+cosx)×1sinxcosx=(sinx+cosx)×22sinxcosx=a×2a2−1sosinx+cosx+tanx+cotx+secx+cosecx=a+2a2−1+2aa2−1=a+2(a+1)(a+1)(a−1)=a+2a−1whena=2=21+22−1=2+2(2+1)=32+2=3×1.41+2=6.23somodof∣6.23∣=6.23whena=−2=−21+2−2−1=−21−2(2−1)(2+1)(2−1)=−2−22+2=2−32=−2.23somodof−2.23∣−2.23∣=2.23henceminimumvalue=2.23
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