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Question Number 65743 by aliesam last updated on 03/Aug/19

Commented by ~ À ® @ 237 ~ last updated on 04/Aug/19

On a 1=∣1∣=∣1+(y−z)−(y−z)∣ =∣1+y−z −[(y−x)+(x−z)]∣ = ∣ (1+y−z)+(x−y)+(−(x−z))∣ quand tu appliques la sous additivite 1< ∣1+y−z∣+∣x−y∣+∣−(x−z)∣ cqfd

Ona1=∣1∣=∣1+(y−z)−(y−z)∣=∣1+y−z−[(y−x)+(x−z)]∣=∣(1+y−z)+(x−y)+(−(x−z))∣quandtuappliqueslasousadditivite1<∣1+y−z∣+∣x−y∣+∣−(x−z)∣cqfd

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