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Question Number 65929 by Masumsiddiqui399@gmail.com last updated on 06/Aug/19

Commented by kaivan.ahmadi last updated on 06/Aug/19

cot1=tan89  cot2=tan88  ⋮  cot44=tan46  since  tan((π/2)−α)=cotα    S=(tan^2 1+cot^2 1)+(tan^2 2+cot^2 2)+...+(tan^2 44+cot^2 44)+tan^2 45=

cot1=tan89cot2=tan88cot44=tan46sincetan(π2α)=cotαS=(tan21+cot21)+(tan22+cot22)+...+(tan244+cot244)+tan245=

Commented by Tony Lin last updated on 08/Aug/19

Answered by MJS last updated on 06/Aug/19

((15931)/3)=((89×179)/3)

159313=89×1793

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