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Question Number 66044 by rajesh4661kumar@gmail.com last updated on 08/Aug/19
Answered by Tanmay chaudhury last updated on 08/Aug/19
∫dxx5(1+1x4)34t=1+1x4→dt=−4x5dx∫dt−4×t34−14×t−34+1−34+1+c(−1)(1+1x4)14+c
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