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Question Number 66476 by aliesam last updated on 15/Aug/19

Commented by kaivan.ahmadi last updated on 15/Aug/19

t=4x+1⇒ (((t−1)^2 )/(((√t)−1)^2 ))=t+2⇒((((√t)−1)^2 ((√t)+1)^2 )/(((√t)−1)^2 ))=t+2⇒ ((√t)+1)^2 =t+2⇒t+1+2(√t)=t+2⇒2(√t)=1⇒(√t)=(1/2)⇒ t=(1/4)⇒ x=((t−1)/4)=(((1/4)−1)/4)=((−3)/(16))

t=4x+1⇒(t−1)2(t−1)2=t+2⇒(t−1)2(t+1)2(t−1)2=t+2⇒(t+1)2=t+2⇒t+1+2t=t+2⇒2t=1⇒t=12⇒t=14⇒x=t−14=14−14=−316

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