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Question Number 67072 by TawaTawa last updated on 22/Aug/19

Answered by mr W last updated on 22/Aug/19

Commented by mr W last updated on 22/Aug/19

side length =25+15=40  ((SQ)/(AP))=((QB)/(AB))=(2/(2+3))=(2/5)  ⇒SQ=(2/5)×25=10  ⇒QB=(2/(2+3))×40=16  ((RT)/(QB−RT))=((BC)/(SQ))=((40)/(10))=4  ((RT)/(16−RT))=4  5×RT=64  ⇒RT=((64)/5)  A_(green) =(1/2)×40×((64)/5)=256 cm^2

sidelength=25+15=40SQAP=QBAB=22+3=25SQ=25×25=10QB=22+3×40=16RTQBRT=BCSQ=4010=4RT16RT=45×RT=64RT=645Agreen=12×40×645=256cm2

Commented by TawaTawa last updated on 22/Aug/19

God bless you sir. I really appreciate.

Godblessyousir.Ireallyappreciate.

Commented by TawaTawa last updated on 22/Aug/19

Sir, please i don′t understand this rule:   ((RT)/(QB − RT))  =  ((BC)/(SQ))  i understand the rest as similar triangle.  Thanks for your time sir

Sir,pleaseidontunderstandthisrule:RTQBRT=BCSQiunderstandtherestassimilartriangle.Thanksforyourtimesir

Commented by mr W last updated on 22/Aug/19

Commented by mr W last updated on 22/Aug/19

((RT)/(UR))=((CB)/(SQ))  UR=QB−RT  ((RT)/(QB−RT))=((CB)/(SQ))  ((RT)/(16−RT))=((40)/(10))=4  5×RT=64  ⇒RT=((64)/5)

RTUR=CBSQUR=QBRTRTQBRT=CBSQRT16RT=4010=45×RT=64RT=645

Commented by TawaTawa last updated on 22/Aug/19

I understand this now sir. very clear, God bless you sir.    But what rule is:       ((RT)/(UR)) = ((CB)/(SQ))

Iunderstandthisnowsir.veryclear,Godblessyousir.Butwhatruleis:RTUR=CBSQ

Commented by TawaTawa last updated on 22/Aug/19

I know similar triangle but i dont know when to use the above sir

Iknowsimilartrianglebutidontknowwhentousetheabovesir

Commented by mr W last updated on 22/Aug/19

((RT)/(UR))=((RC)/(RQ))=((CB)/(SQ))

RTUR=RCRQ=CBSQ

Commented by TawaTawa last updated on 22/Aug/19

I appreciate your time sir.  I have new question on the group sir.

Iappreciateyourtimesir.Ihavenewquestiononthegroupsir.

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