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Question Number 6788 by Tawakalitu. last updated on 26/Jul/16

Commented by Yozzii last updated on 27/Jul/16

$$60=6\times 10=\left(3\times 2\right)(7+3)$$$$17,23,32$$$$Addthetwolargestunitdigitvaluesamong$$$$thethreenumbers\left(3\mathrm{\&}7\right)andmultiplythis$$$$answerwiththetwolargestdigitvaluesin$$$$tenscolumns\left(2\mathrm{\&}3\right)\Rightarrow (7+3)\times 2\times 3=60.$$$$--------------------$$$$13,23,?\to 42$$$$42=2\times 3\times 7=2\times 3\times (3+4)$$$$13,23,34\Rightarrow 2\times 3\times (3+4)=42$$$$?=34possibly$$

Commented by Tawakalitu. last updated on 27/Jul/16

$$Ireallyappreciateyoureffort$$

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