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Question Number 67963 by mhmd last updated on 02/Sep/19
Commented by mathmax by abdo last updated on 02/Sep/19
generallyifF(x)=∫u(x)v(x)f(t)dt⇒F′(x)=v′(x)f(v(x))−u′(x)f(u(x))wehaveF(x)=∫0xtsin(t)dt⇒F′(x)=(x)′(xsinx)−(0)′(0sin0)=xsinx.
Answered by mr W last updated on 02/Sep/19
ifG′(x)=xsinx,thenF(x)=∫0xtsintdt=G(x)−G(0)⇒F′(x)=G′(x)−0=xsinx
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