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Question Number 68132 by mr W last updated on 05/Sep/19
Commented by kaivan.ahmadi last updated on 05/Sep/19
a+β+θ=180(1)α+β−a=0(2)2α−2θ+b=0(3)(3)−(2):α−2θ−β+(a+b)=0⇒2θ+β−α=120(4)(1)−(2):2a+θ−α=180(1)+(3):2α+β−θ+(a+b)=180⇒2α+β−θ=60(5)2(5)+(4):3α+3β=240⇒α+β=80(6)from(2)and(6)wehave80−a=0⇒a=80
Commented by mr W last updated on 06/Sep/19
thankyou!
Commented by TawaTawa last updated on 06/Sep/19
Great,Godblessyousir.Iunderstand
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