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Question Number 68132 by mr W last updated on 05/Sep/19

Commented by kaivan.ahmadi last updated on 05/Sep/19

a+β+θ=180   (1)  α+β−a=0     (2)  2α−2θ+b=0   (3)  (3)−(2): α−2θ−β+(a+b)=0⇒2θ+β−α=120   (4)  (1)−(2): 2a+θ−α=180  (1)+(3): 2α+β−θ+(a+b)=180⇒2α+β−θ=60   (5)  2(5)+(4): 3α+3β=240⇒α+β=80  (6)  from (2) and (6)we have 80−a=0⇒a=80

a+β+θ=180(1)α+βa=0(2)2α2θ+b=0(3)(3)(2):α2θβ+(a+b)=02θ+βα=120(4)(1)(2):2a+θα=180(1)+(3):2α+βθ+(a+b)=1802α+βθ=60(5)2(5)+(4):3α+3β=240α+β=80(6)from(2)and(6)wehave80a=0a=80

Commented by mr W last updated on 06/Sep/19

thank you!

thankyou!

Commented by TawaTawa last updated on 06/Sep/19

Great, God bless you sir. I understand

Great,Godblessyousir.Iunderstand

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