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Question Number 69183 by Tony Lin last updated on 21/Sep/19

Commented by Tony Lin last updated on 21/Sep/19

$49 . m_{1} g = (m_{1} + m_{2}) a$ $\Rightarrow a = \frac{m_{1} g}{m_{1} + m_{2}}$ $\Rightarrow F = (M + m_{1} + m_{2}) a = \frac{m_{1} g (M + m_{1} + m_{2})}{m_{1} + m_{2}}$ $I^{'} m n o t s u r e o f t h e d i r e c t i o n o f a_{m_{1}}$ $i s \to o r ↓ ?$ $O r m y m e t h o d h a s m i s t a k e s ?$
Commented by Tony Lin last updated on 21/Sep/19

$53 . D o e s t h i s e x a m p l e s a t i s f i e s t h e$ $c o n s e r v a t i o n o f h o r i z o n t a l m o m e n t u m ?$ $I f Y e s, h o w t o s o l v e i t ?$
	Answered by mr W last updated on 21/Sep/19

	Commented by mr W last updated on 21/Sep/19

	$(n o t e : i n m y s o l u t i o n m_{1} c o r r e s p o n d s$ $w i t h m_{2} i n t h e q u e s t i o n a n d m_{2} w i t h$ $m_{1})$ $a l l b l o c k s m u s t h a v e t h e s a m e h o r i z o n t a l$ $m o t i o n a n d n o v e r t i c a l m o t i o n .$ $T = m_{2} g$ $N_{2} = m_{2} a$ $N_{1} = m_{1} g$ $T = m_{1} a = m_{2} g$ $\Rightarrow a = \frac{m_{2}}{m_{1}} g$ $F - N_{2} - T = M a$ $\Rightarrow F = M a + N_{2} + T = M a + m_{2} a + m_{1} a$ $\Rightarrow F = (M + m_{2} + m_{1}) a = \frac{(M + m_{1} + m_{2}) m_{2} g}{m_{1}}$
	Commented by Tony Lin last updated on 21/Sep/19

	$T h a n k s, I g o t i t .$
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