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Question Number 7147 by Tawakalitu. last updated on 13/Aug/16
Commented by Yozzii last updated on 13/Aug/16
u(n)=(−1+2)+(−3+4)+(−5+6)+...+(−(2n−1)+2n)u(n)=∑ni=1(−2n+1+2n)=nu(1092)=1092109+∑109k=0k(−1)k=109+∑109k=1k(−1)k=3×1092
Commented by Tawakalitu. last updated on 13/Aug/16
Thankssomuchsir.ireallyappreciate
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