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Question Number 76442 by aliesam last updated on 27/Dec/19

Answered by Tanmay chaudhury last updated on 28/Dec/19

$$x=tanadx={sec}^{2}ada$$$${sec}^{-1}\left(\frac{1+{tan}^{2}a}{1-{tan}^{2}a}\right)\to {sec}^{-1}\left(sec2a\right)=2a$$$$\int \frac{2a}{tana\times a}\times {sec}^{2}ada$$$$2\int \frac{d\left(tana\right)}{tana}\to 2\mathit{l}\mathit{n}\left(\mathit{t}\mathit{a}\mathit{n}\mathit{a}\right)$$$$\mathit{s}\mathit{o}2\mid \mathit{l}\mathit{n}\mathit{x}{\mid }_e^{e^2}=soansweris2({lne}^2-lne)=2(2-1)=2$$

Commented by aliesam last updated on 28/Dec/19

$$godblessyousir$$

Commented by Tanmay chaudhury last updated on 28/Dec/19

$$thankyousir$$

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