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Question Number 7775 by sandy_suhendra last updated on 14/Sep/16

Commented by sou1618 last updated on 15/Sep/16

x=4−(√3) x^4 −6x^3 −2x^2 +18x+23=? (x−4+(√3))(x−4−(√3))=0 (∵x=4−(√3)) ⇒x^2 −8x+13=0 (x^4 −6x^3 −2x^2 +18x+23)÷(x^2 −8x+13) =(x^2 +2x+1)+((10)/(x^2 −8x+13)) so x^4 −6x^3 −2x^2 +18x+23=(x^2 −8x+13)(x^2 +2x+1)+10 =10

x=4−3x4−6x3−2x2+18x+23=?(x−4+3)(x−4−3)=0(∵x=4−3)⇒x2−8x+13=0(x4−6x3−2x2+18x+23)÷(x2−8x+13)=(x2+2x+1)+10x2−8x+13sox4−6x3−2x2+18x+23=(x2−8x+13)(x2+2x+1)+10=10

Commented by sandy_suhendra last updated on 15/Sep/16

Nice, thank′s for your answer

Nice,thank′sforyouranswer

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