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Question Number 78161 by TawaTawa last updated on 14/Jan/20

Answered by mr W last updated on 15/Jan/20

$$M=5kg$$$$m=2kg$$$$T-\mu mg=ma$$$$F-T-\mu mg-\mu (m+Mg)=Ma$$$$F-\mu (3m+M)g=(m+M)a$$$$\Rightarrow a=\frac{F-\mu (3m+M)g}{m+M}=\frac{80-0.44\times 11\times 10}{7}$$$$=4.51m/s^2$$

Commented by TawaTawa last updated on 15/Jan/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by TawaTawa last updated on 15/Jan/20

$$\mathrm{I}\mathrm{appreciate}$$

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