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Question Number 78564 by physics.is.love last updated on 18/Jan/20

Commented by physics.is.love last updated on 18/Jan/20

$$pleaseexplain$$

Answered by key of knowledge last updated on 18/Jan/20

$$8\mathrm{v};\mathrm{i}=0\left(\mathrm{see}\mathrm{battery}\right)$$$${\mathrm{V}}_{\mathrm{A}}+\left(0\times 4\right)+8+\left(0\times 2\right)={\mathrm{V}}_{\mathrm{B}}$$$${\mathrm{V}}_{\mathrm{B}}-{\mathrm{V}}_{\mathrm{A}}=8\mathrm{v}$$

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