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Question Number 85059 by Power last updated on 18/Mar/20

	Answered by MJS last updated on 18/Mar/20

	$x^{5} + 1 =$ $= (x + 1) (x^{2} - \frac{1 - \sqrt{5}}{2} x + 1) (x^{2} - \frac{1 + \sqrt{5}}{2} x + 1)$ ${you}^{'} ll have to decompose and then use$ $formulas$ $c_{2} \int \frac{d x}{x + c_{1}}$ $and$ $c_{4} \int \frac{x + c_{1}}{x^{2} + c_{2} x + c_{3}} d x$ $you can find in any good formulary$
	Commented by Power last updated on 19/Mar/20

	$step by step solution$
	Commented by mr W last updated on 19/Mar/20

	$P o w e r s i r :$ $i t h i n k a l i t t l e b i t t h i n g s h o u l d b e l e f t$ $f o r y o u t o d o b y y o u r s e l f . y o u a r e n o t$ $o u r t e a c h e r a n d w e a r e n o t y o u r$ $s t u d e n t s . t h a t s h o u l d b e c l e a r .$ $i t h i n k w h e n s o m e o n e b r i n g s$ $m e f o o d, i {d o n}^{'} t r e q u e s t i h m t o p u t$ $t h e f o o d i n m y m o u t h . t h a t s h o u l d b e$ $d o n e b y m y s e l f!$ $b u t w h e n p e o p l e g i v e y o u h i n t f o r h o w$ $t o s o l v e a p r o b l e m, y o u s e e m o n l y$ $t o k n o w t o a s k f o r m o r e . p e r s o n a l l y$ $i d i s l i k e t h i s k i n d o f b e h a v i o u r .$
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