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Question Number 85228 by mathocean1 last updated on 20/Mar/20
Commented by mathocean1 last updated on 20/Mar/20
pleasehelpme...
Commented by abdomathmax last updated on 20/Mar/20
Cnp−Cn−1p=n!p!(n−p)!−(n−1)!p!(n−p−1)!=n(n−1)!p(p−1)!(n−p)!−(n−1)!(n−p)p(p−1)!(n−p)!=(n−1)!(p−1)!(n−p)!{np−n−pp}=(n−1)!(p−1)!(n−p)!×1=Cn−1p−1⇒Cnp=Cn−1p+Cn−1p−1
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