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Question Number 85950 by TawaTawa1 last updated on 26/Mar/20

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{Which}\mathrm{colour}\mathrm{area}\mathrm{is}\mathrm{bigger}.$$$$\mathrm{please}\mathrm{show}\mathrm{workings}.$$

Answered by jagoll last updated on 26/Mar/20

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{blue}\mathrm{area}=2\times (\frac{1}{4}\pi {\mathrm{R}}^2-\frac{1}{2}{\mathrm{R}}^2)$$$$={\mathrm{R}}^2(\frac{1}{2}\pi -1)=\frac{1}{2}{\mathrm{R}}^2(\pi -2)$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{black}\mathrm{area}=\frac{1}{4}\pi {\left(2\mathrm{R}\right)}^2-(\frac{1}{2}\pi {\mathrm{R}}^2+{\mathrm{R}}^2)$$$$=\pi {\mathrm{R}}^2-\frac{1}{2}\pi {\mathrm{R}}^2-{\mathrm{R}}^2$$$$=\frac{1}{2}\pi {\mathrm{R}}^2-{\mathrm{R}}^2=\frac{1}{2}{\mathrm{R}}^2(\pi -2)$$

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$$$\mathrm{I}\mathrm{appreciate}\mathrm{your}\mathrm{time}.$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{blue}\mathrm{area}=\mathrm{black}\mathrm{area}.$$

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{Sir},\mathrm{please}\mathrm{explain}\mathrm{the}\mathrm{blue}\mathrm{area}\mathrm{why}\mathrm{it}\mathrm{is}2\times (\frac{1}{4}\pi {\mathrm{R}}^2-\frac{1}{2}{\mathrm{R}}^2)$$

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{Also}\mathrm{black}\mathrm{area}\mathrm{same}\mathrm{thing}.$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{the}\mathrm{blue}\mathrm{area}\mathrm{is}\mathrm{twice}\mathrm{the}\mathrm{width}$$$$\mathrm{of}\mathrm{the}\mathrm{circle}$$

Commented by jagoll last updated on 26/Mar/20

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{look}\mathrm{at}\mathrm{picture}$$

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{Alright}\mathrm{sir},\mathrm{what}\mathrm{of}\frac{1}{4}\pi {\mathrm{R}}^2.\mathrm{and}\frac{1}{2}\pi {\mathrm{R}}^2$$$$\mathrm{Sorry}\mathrm{for}\mathrm{two}\mathrm{many}\mathrm{question}\mathrm{sir}$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{in}\mathrm{blue}\mathrm{are},\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{one}\mathrm{tile}$$$$\mathrm{is}\mathrm{a}\mathrm{quarter}\mathrm{of}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{a}\mathrm{circle}$$$$\mathrm{minus}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{a}\mathrm{triangle}$$$$$$

Commented by TawaTawa1 last updated on 26/Mar/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}.$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{thank}\mathrm{you}$$

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