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Question Number 8607 by tawakalitu last updated on 17/Oct/16

Answered by ridwan balatif last updated on 18/Oct/16

$$23.\mathrm{C}=0.50\mu \mathrm{F}=5\times {10}^{-7}\mathrm{F}$$$$\mathrm{L}=0.050\mathrm{H}$$$$\mathrm{f}=\frac{100}{\pi }$$$$\omega =2\pi \mathrm{f}$$$$\omega =200\mathrm{rad}/\mathrm{s}$$$$\left(\mathrm{i}\right){\mathrm{X}}_{\mathrm{C}}=\frac{1}{\omega \times \mathrm{C}}=\frac{1}{200\times 5\times {10}^{-7}}={10}^4\mathrm{\Omega }$$$$\left(\mathrm{ii}\right){\mathrm{X}}_{\mathrm{L}}=\omega \times \mathrm{L}=200\times 0.05=10\mathrm{\Omega }$$

Commented by tawakalitu last updated on 18/Oct/16

$$\mathrm{Thank}\mathrm{you}\mathrm{for}\mathrm{your}\mathrm{help}.$$

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