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Question Number 8609 by tawakalitu last updated on 17/Oct/16

Answered by ridwan balatif last updated on 18/Oct/16

Answered by ridwan balatif last updated on 18/Oct/16

Commented by tawakalitu last updated on 18/Oct/16

$$\mathrm{I}\mathrm{really}\mathrm{appreciate}\mathrm{sir}.$$

Answered by sandy_suhendra last updated on 18/Oct/16

Commented by sandy_suhendra last updated on 18/Oct/16

$$\mathrm{let}\mathrm{the}\mathrm{sport}\mathrm{car}\mathrm{overtakes}\mathrm{the}\mathrm{car}\mathrm{at}\mathrm{t}\mathrm{second}\mathrm{after}\mathrm{the}\mathrm{car}\mathrm{passes}\mathrm{the}\mathrm{sport}\mathrm{car}$$$$\mathrm{the}\mathrm{distance}\mathrm{of}\mathrm{the}\mathrm{car}=\mathrm{the}\mathrm{area}\mathrm{below}\mathrm{the}\mathrm{graph}\mathrm{of}\mathrm{the}\mathrm{car}=20\mathrm{t}\mathrm{meter}$$$$\mathrm{the}\mathrm{distance}\mathrm{of}\mathrm{the}\mathrm{sport}\mathrm{car}=\mathrm{the}\mathrm{area}\mathrm{below}\mathrm{the}\mathrm{graph}\mathrm{of}\mathrm{the}\mathrm{sport}\mathrm{car}=\frac{\mathrm{t}-10+\mathrm{t}-20}{2}\times 30=(30\mathrm{t}-450)\mathrm{meter}$$$$\mathrm{the}\mathrm{sport}\mathrm{car}\mathrm{will}\mathrm{overtake}\mathrm{the}\mathrm{car}\mathrm{if}$$$$20\mathrm{t}=30\mathrm{t}-450$$$$\mathrm{t}=45\mathrm{second}$$$$\mathrm{at}\mathrm{the}\mathrm{distance}=20\times 45=900\mathrm{meter}$$

Commented by tawakalitu last updated on 18/Oct/16

$$\mathrm{i}\mathrm{really}\mathrm{appreciate}.$$

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