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Question Number 86802 by oustmuchiya@gmail.com last updated on 31/Mar/20

Commented by Rio Michael last updated on 31/Mar/20

$$???$$

Answered by Rio Michael last updated on 31/Mar/20

$$\left(3\right)x^0+x^2=5\Rightarrow x=\pm 2.$$$$\left(4\right){(\mathrm{A}\cup \mathrm{B})}^{{}^{\prime }}=\{7,8\}.$$$$\left(5\right)\left(\mathrm{a}\right)\mathrm{tras}\mathrm{A}=\left(\begin{array}{cc}-1& 2\\ 4& 3\end{array}\right)$$$$\left(\mathrm{b}\right)2x^2=8\Rightarrow x=\pm 2$$$$\left(6\right)d=\frac{10}{-6}=-\frac{5}{3}$$$$\frac{v}{t-a}=d\Rightarrow a=t-\frac{v}{d}$$$$$$

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