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Question Number 87418 by liki last updated on 04/Apr/20

Answered by Rio Michael last updated on 04/Apr/20

$$\left(\mathrm{a}\right)\mathrm{since}\mathrm{we}\mathrm{have}3\mathrm{match}\mathrm{pairs}\mathrm{in}\mathrm{the}\mathrm{box},\mathrm{then}$$$$\mathrm{P}\left(\mathrm{match}\mathrm{pair}\right)=\frac{1}{3}.$$$$\left(\mathrm{b}\right)\mathrm{we}\mathrm{have}\mathrm{six}\mathrm{socks}\mathrm{in}\mathrm{that}\mathrm{box},3\mathrm{left}\mathrm{feet}\mathrm{and}3\mathrm{right}\mathrm{fit}$$$$\mathrm{P}\left(\mathrm{left}\mathrm{feet}\right)=\frac{1}{3}\mathrm{and}\mathrm{P}\left(\mathrm{right}\mathrm{feet}\right)=\frac{1}{3}$$$$\Rightarrow \mathrm{P}\left(\mathrm{left}\mathrm{and}\mathrm{right}\right)=\frac{1}{3}\times \frac{1}{3}=\frac{1}{9}\mathrm{since}\mathrm{they}\mathrm{are}\mathrm{independent}\mathrm{events}$$$$\left(\mathrm{c}\right)\mathrm{P}\left(2\mathrm{socks}\mathrm{of}\mathrm{right}\mathrm{feet}\right)=\frac{2}{3}$$$$\left(\mathrm{d}\right)\mathrm{P}\left(\mathrm{RR}\mathrm{or}\mathrm{LL}\right)=\frac{1}{9}+\frac{1}{9}=\frac{2}{9}$$

Commented by liki last updated on 04/Apr/20

$$....thankyousir,$$

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