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Question Number 87975 by ajfour last updated on 07/Apr/20

Commented by ajfour last updated on 07/Apr/20

$$Findradiusofcircle.$$

Commented by Tony Lin last updated on 07/Apr/20

Commented by Tony Lin last updated on 07/Apr/20

$$\frac{4}{3}r=k{\left(\frac{4\sqrt{2}}{3}r\right)}^2$$$$\Rightarrow r=\frac{3}{8k}$$

Commented by Tony Lin last updated on 07/Apr/20

$$Istheequationofparabolaunknown?$$

Commented by ajfour last updated on 07/Apr/20

$$yes,mustbey=?x^2.$$$$?tobedetermined..$$

Commented by ajfour last updated on 07/Apr/20

$$Igotkr=\frac{3}{4},andthereseems$$$$\left(tomenow\right),that{something}^{\prime }s$$$$wrongwiththisquestion(ithought$$$$ofmyself..)$$

Commented by Tony Lin last updated on 07/Apr/20

$$yeah,m_{AD}=-\frac{\sqrt{2}}{4}$$$$y^{{}^{\prime }}{\mid }_{x=\frac{4\sqrt{2}}{3}r}=2kx=2k\left(\frac{4\sqrt{2}}{3}r\right)=\frac{8\sqrt{2}}{3}kr$$$$\frac{8\sqrt{2}}{3}kr=2\sqrt{2}$$$$kr=\frac{3}{4}\ne \frac{3}{8}$$

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