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Question Number 87991 by necxxx last updated on 07/Apr/20

Commented by necxxx last updated on 07/Apr/20

$p l e a s e h e l p$
	Answered by mr W last updated on 07/Apr/20

	$R = r a d i u s o f b i g s e m i c i r c l e$ $r = r a d i u s o f s m a l l s e m i c i r c l e$ $b = l e n g t h o f c h o r d$ $R^{2} - r^{2} = {(\frac{b}{2})}^{2}$ $\frac{π}{2} R^{2} - \frac{π}{2} r^{2} = \frac{b^{2} π}{8}$ $b i g - s m a l l s e m i c i r c l e = \frac{b^{2} π}{8}$ $b l u e a r e a = \frac{b^{2} π}{8} = \frac{12^{2} π}{8} = 18 π$
	Commented by necxxx last updated on 07/Apr/20

	$w o w . . w h a t a n e y e o p e n e r . T h a n k y o u$ $s i r$
	Commented by necxxx last updated on 07/Apr/20

	$p l e a s e s i r I j u s t t r i e d t o u n d e r s t a n x t h a t$ $f o r m u l a y o u u s e d a n d I^{'} m s t u c k .$ $h o w i s t h e a r e a o f t h e b l u e r e g i o n = (\frac{12^{2}}{8_{}} π) ?$
	Commented by mr W last updated on 07/Apr/20

	$b l u e a r e a = b i g s e m i c i r c l e - s m a l l s e m i c i r c l e$ $b i g s e m i c i r c l e = \frac{π R^{2}}{2} a s a l l e a r t h p e o p l e k n o w$ $s m a l l s e m i c i r c l e = \frac{π r^{2}}{2} a s a l l e a r t h p e o p l e k n o w$ $\Rightarrow b l u e a r e a = \frac{π R^{2}}{2} - \frac{π r^{2}}{2}$ $s i n c e \frac{π}{2} R^{2} - \frac{π}{2} r^{2} = \frac{b^{2} π}{8} a s p r o v e d$ $\Rightarrow b l u e a r e a = \frac{b^{2} π}{8}$ $s i n c e b = 12 a s g i v e n$ $\Rightarrow b l u e a r e a = \frac{12^{2} π}{8} = 18 π$
	Commented by $@ty@m123 last updated on 07/Apr/20

	$W o n n d e r f u l!$
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