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Question Number 88021 by naka3546 last updated on 07/Apr/20

Commented by MJS last updated on 07/Apr/20

$I get 4 \lor 5 . . . not sure how I got there . . .$
Commented by naka3546 last updated on 08/Apr/20

${y o u}^{'} r e r i g h t, s i r .$
	Answered by $@ty@m123 last updated on 08/Apr/20
	$p+q+r+s=9 {where p=(a/b) and so on pq+qr+rs+sp=20 ⇒(p+r)(q+s)=20 Equation whose roots are p+r, q+s is x^2 −9x+20=0 x=4,5$
	$p + q + r + s = 9 {w h e r e p = \frac{a}{b} a n d s o o n$ $p q + q r + r s + s p = 20$ $\Rightarrow (p + r) (q + s) = 20$ $E q u a t i o n w h o s e r o o t s a r e p + r, q + s i s$ $x^{2} - 9 x + 20 = 0$ $x = 4, 5$
	Commented by Prithwish Sen 1 last updated on 08/Apr/20

	$I think it will be$ $(p + r) (q + s) = 20$
	Commented by $@ty@m123 last updated on 08/Apr/20

	$T h a n k s f o r c o r r e c t i o n .$
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