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Question Number 88306 by TawaTawa1 last updated on 09/Apr/20

Commented by mr W last updated on 10/Apr/20

$$pleasetryagain.{it}^{\prime }ssoobvious,just$$$$connectthecentersofbothcircles.$$

Commented by mr W last updated on 09/Apr/20

$${(8-3-r)}^2+{(6-3-r)}^2={(3+r)}^2$$$$r^2-22r+25=0$$$$\Rightarrow r=11-4\sqrt{6}\approx 1.202$$

Commented by TawaTawa1 last updated on 09/Apr/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Commented by TawaTawa1 last updated on 09/Apr/20

$$\mathrm{My}\mathrm{problem}\mathrm{is}\mathrm{how}\mathrm{you}\mathrm{get}\mathrm{the}\mathrm{equation}\mathrm{sir}.$$$$\mathrm{I}\mathrm{can}\mathrm{expand}\mathrm{and}\mathrm{simplify}.$$

Commented by TawaTawa1 last updated on 10/Apr/20

$$\mathrm{Alright}\mathrm{sir},\mathrm{i}\mathrm{will}\mathrm{do}\mathrm{that}$$

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