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Question Number 89172 by M±th+et£s last updated on 15/Apr/20

Answered by mahdi last updated on 15/Apr/20

$${\left(\frac{{\mathrm{x}}^1.{\mathrm{x}}^{\frac{-\mathrm{b}}{\mathrm{a}}}.{\mathrm{x}}^{\frac{1}{\mathrm{a}}}.{\mathrm{x}}^{\frac{\mathrm{b}}{{\mathrm{a}}^2}}}{{\mathrm{x}}^{\frac{\mathrm{b}}{{\mathrm{a}}^2}}.{\mathrm{x}}^{\frac{\mathrm{a}}{\mathrm{a}}}}\right)}^{\frac{1}{\mathrm{b}-1}}={\left({\mathrm{x}}^{\frac{1-\mathrm{b}}{\mathrm{a}}}\right)}^{\frac{1}{\mathrm{b}-1}}={\mathrm{x}}^{\frac{-1}{\mathrm{a}}}=\frac{1}{\sqrt[\mathrm{a}]{\mathrm{x}}}$$

Commented by M±th+et£s last updated on 15/Apr/20

$$perfect.thankyousir$$

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