Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 89194 by ajfour last updated on 16/Apr/20

Commented by ajfour last updated on 16/Apr/20

$$Givenparabolaisy=x^2,and$$$$ifOB=AB=BC=s,finds.$$

Commented by john santu last updated on 16/Apr/20

$$letA(a,a^2),B(0,s),C(0,2s)$$$$\sqrt{a^2+{(a^2-s)}^2}=s$$$$a^2+a^4-2a^{2}s+s^2=s^2$$$$s=\frac{a^2+1}{2}.\left(i\right)$$$$ithinkthequestionnotcomplete$$

Answered by mr W last updated on 16/Apr/20

$$B(0,s)$$$$C(0,2s)$$$$D(-\sqrt{2s},2s)$$$$A(a,a^2)$$$$eqn.ofDBA:$$$$\frac{y-s}{x}=\frac{2s-s}{-\sqrt{2s}}$$$$\Rightarrow y=s-\frac{\sqrt{2s}}{2}x$$$$a^2=s-\frac{\sqrt{2s}}{2}a$$$$a^2+\frac{\sqrt{2s}}{2}a-s=0$$$$a=\frac{1}{2}(-\frac{\sqrt{2s}}{2}+\frac{3\sqrt{2s}}{2})=\frac{\sqrt{2s}}{2}$$$$a^2+{(s-a^2)}^2=s^2$$$$\frac{s}{2}+{(s-\frac{s}{2})}^2=s^2$$$$\Rightarrow s=\frac{2}{3}$$

Commented by mr W last updated on 16/Apr/20

$$exactlythesameasbymebeforei$$$$checkedongraph.imisread\sqrt{2s}as\sqrt{2}s.$$

Commented by ajfour last updated on 16/Apr/20

$$Correctsir,Perfect!$$

Commented by mr W last updated on 16/Apr/20

Commented by ajfour last updated on 16/Apr/20

$$ialsosolved,gots=2\pm \sqrt{2},buti$$$$dintliketwovalues,sochecked,$$$$foundsomeerror,thengot\frac{2}{3}.$$$$whatacoincidence,Sir!$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com