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Question Number 89422 by naka3546 last updated on 17/Apr/20
Commented by jagoll last updated on 17/Apr/20
f(x)=(x+2)(x+1)f(A)=(A+2I)(A+I)
Answered by som(math1967) last updated on 17/Apr/20
f(A)=A2+3A+2I=[1−22−1][1−22−1]+3[1−22−1]+2[1001]=[−300−3]+[3−66−3]+[2002]=[−3+3+20−6+00+6+0−3−3+2]=|2−66−4|....ansB
Commented by naka3546 last updated on 17/Apr/20
thankyou
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